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GEOMETRIC SERIES A series is a sequence of possibly infinitely many terms whose sum is to be determined. A geometric series is a series in which each term is the same multiple of its predecessor. For example, 20 + 60 + 180 + 540 + 1620 + 4860 + is a geometric series because each term is 3 times the size of its predecessor. The multiplier 3 is called the common ratio of the series. Theorem A.5 Sum of a Finite Geometric Series If r 1, then a 1 rn = --------------------1 r Here, a is the first term in the series, r is the common ratio, and n is the number of terms in the series. a + ar + ar + ar +

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For every k > 0, nk = o(2n ), because nk/2n 0. k = o(n), because (lgn)k/n 0. For every k > 0, (lgn) For every base b > 1, log b n = (lgn), because log b n/lg n = log b 2. 0. The factorial numbers n! = (2n ), because 2n/n!

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For the sum 20 + 60 + 180 + 540 + 1620 + 4860, the three parameters are a = 20, r = 3, and n = 6. So the sum is a 1 r 20 1 3 20 1 729 20 729 -------------------- = ------------------------ = ---------------------------- = ---------------------- = 7280 1 r 1 3 2 2

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To design a discrete-time high-pass filter, there are two approaches that we may use. We may design an analog type I Chebyshev low-pass filter, map it into a Chebyshev low-pass filter using the bilinear transformation, and then perform a low-pass-to-high-pass transformation in the z-domain. Alternatively, before applying the bilinear transformation. we could perform a low-pass-to-high-pass transformation in the s-plane and then map the analog high-pass filter into a discrete-time high-pass filter using the bilinear transformation. Because both methods result in the same design, it does not matter which method we use. Therefore, we will use the second approach, because it is a little easier algebraically. Given that we want lo design a high-pass filter with a stopband cutoff frequency ws = 0.117 and a passband cutoff frequency w, = 0.317, we first transform the specifications of the digital filter into the continuous-time domain. With T, = 2 and W R = tan -

APPENDIX]

Using the transformation s -+ I 1s to map these high-pass filter cutoff frequencies to low-pass filter cutoff frequencies, we have

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Theorem A.6 Sum of an Infinite Geometric Series If 1 < r < 1, then a 2 3 a + ar + ar + ar + = ---------1 r EXAMPLE A.7 Infinite Geometric Series

Although we should round up to N = 3, with a second-order Chebyshev filter we should come close to meeting the specifications. Therefore, we will use N = 2. The next step is to design a second-order low-pass Chebyshev filter with

The five complexity classes can be imprecisely described by these phrases: f(n) = o(g(n)) means that f(n) grows more slowly than g(n). f(n) = O(g(n)) means that f(n) grows more slowly or at the same rate as g(n). f(n) = (g(n)) means that f(n) grows at the same rate g(n). f(n) = (g(n)) means that f(n) grows faster or at the same rate as g(n). f(n) = (g(n)) means that f(n) grows faster than g(n). EXAMPLE A.3 Asymptotic Growth Classes

For the sum 0.42 + 0.0042 + 0.000042 + 0.00000042 + 0.0000000042 + a = 0.42 and r = 0.01. So the infinite sum is a0.42 ---------- = ------------------ = 0.42 = 42 = 14 ----------------1 r 1 0.01 0.99 99 33 , the three parameters are

For a second-order Chebyshev filter, we need to generate a second-order Chebyshev polynomial. which is

Squaring T2(x), we have T;(X) = 4x4 - 4x2 + I and, for the magnitude squared frequency response of the Chebyshev filter, we have

250 lgn = o(n), because 250 lgn grows more slowly than n. 0.086 n lgn = (n), because 0.086 n lgn grows faster than n.

Note that 14/33 = 0.4242424242 . This repeating decimal is obviously the same as the infinite sum 0.42 + 0.0042 + 0.000042 + 0.00000042 + 0.0000000042 + .

Next, we find H4(s)H4(-s) with the substitution St = -js,

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