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class MyClass { // This iterator returns the letters // A, B, C, D, and E public IEnumerator GetEnumerator() { yield return 'A'; yield return 'B'; yield return 'C'; yield return 'D'; yield return 'E'; } } class ItrDemo5 { static void Main() { MyClass mc = new MyClass(); foreach(char ch in mc) ConsoleWrite(ch + " "); ConsoleWriteLine(); } }

The output is shown here:

(797)

y = f (x)

Inside GetEnumerator( ), five yield statements occur The important thing to understand is that they are executed one at a time, in order, each time another element in the collection is obtained Thus, each time through the foreach loop in Main( ), one character is returned

// Display a triangle's style public void ShowStyle() { ConsoleWriteLine("Triangle is " + Style); } } class Shapes7 { static void Main() { Triangle t1 = new Triangle("right", 80, 120); // Make a copy of t1 Triangle t2 = new Triangle(t1); ConsoleWriteLine("Info for t1: "); t1ShowStyle(); t1ShowDim(); ConsoleWriteLine("Area is " + t1Area()); ConsoleWriteLine(); ConsoleWriteLine("Info for t2: "); t2ShowStyle(); t2ShowDim(); ConsoleWriteLine("Area is " + t2Area()); } }

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With Eqs (795), (796), and (797), and taking into account the sign of the ordinate of O2, we obtain a cubic equation to determine f: f 3 + 2ef 2 + e 2 f d3 Acam tcam ccam = 0 p tcw (2 d2 + d3 ) (798)

In this program, t2 is constructed from t1 and is, thus, identical The output is shown here:

If we can express the area of the slice at position x as a function A(x) of x, then (see Fig 84) the volume of a slice of thickness x at position x will be about A(x) x If P = {x0 , x1 , , xk } is a partition of the interval [a, b] then the volume of the original solid object will be about V =

Info for t1: Triangle is right Width and height are 8 and 12 Area is 48 Info for t2: Triangle is right Width and height are 8 and 12 Area is 48

It is apparent that having e > a would lead to more unbalance, since this would be equivalent to adding material to the cams, a minimum value of e being preferred in this case Choosing e = a and using the maximum value of tcw, we minimize the counterweight size; in other words, we minimize the radius of the counterweight With these constraints, the value of f can be readily computed For the case of a speed reduction of 8 : 1, we computed the counterweight and created a solid model in Pro/Engineer, as displayed in Fig 726, with the parameters t2 = 5 mm, a = e = 95 mm, b = 235 mm, c = 125 mm, d2 = 985 mm, d3 = 27 mm, tcam = 6 mm, tcw = 8 mm, ccam = 98235 mm, Acam = 16253 106 mm2, and f = 87866 mm

Pay special attention to this Triangle constructor:

public Triangle(Triangle ob) : base(ob) { Style = obStyle; }

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