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18. In a common base circuit, the output is taken from (a) the emitter. (b) the base. (c) the collector. (d) more than one of the above. 19. Suppose that the input signal to a transistor amplifier results in saturation during part of the cycle. This produces (a) the greatest possible amplification. (b) reduced efficiency. (c) avalanche effect. (d) nonlinear output impedance. 20. Suppose that the gain of a transistor in a common emitter circuit is 100 at a frequency of 1 kHz, and the gain is 70.7 at 335 kHz. The gain drops to 1 at 210 MHz. The alpha cutoff frequency is (a) 1 kHz. (b) 335 kHz. (c) 210 MHz. (d) impossible to define based on this data.

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By using diodes and capacitors connected in certain ways, a power supply can be made to deliver a multiple of the peak ac input voltage. Theoretically, large whole-number multiples are possible. But you won t often see power supplies that make use of multiplication factors larger than 2. In practice, voltage multipliers are practical only when the load draws low current. Otherwise, the regulation is poor; the output voltage changes considerably with changes in the load resistance. This bugaboo gets worse and worse as the multiplication factor increases. This is why engineers don t attempt to make, say, a factor-of-16 voltage multiplier. For a good high-voltage power supply, the best approach is to use a step-up transformer, not a voltage multiplier. A voltage-doubler circuit is shown in Fig. 21-7. This circuit works on the whole ac input wave cycle, and is therefore called a full-wave voltage doubler. Its dc output voltage, when the current drawn is low, is about twice the peak ac input voltage, or about 2.8 times the rms ac input voltage.

other major category of transistor is the field effect transistor (FET ). There are two main types of FET: the junction FET (JFET ) and the metal-oxide FET (MOSFET ).

Notice the capacitors in this circuit. The operation of any voltage multiplier is dependent on the ability of these capacitors to hold a charge, even when a load is connected to the output of the supply. Thus, the capacitors must have large values. If the intent is to get a high dc voltage from the supply, massive capacitors will be necessary. Also, notice the resistors in series with the diodes. These have low values, similar to those needed when diodes are connected in parallel. When the supply is switched on, the capacitors draw a huge initial charging current. Without the resistors, it would be necessary to use diodes with astronomical Io ratings. Otherwise the surge current would burn them out.

an incoming lambda strikes one mirror, reflects off a fixed mirrored surface, strikes another movable mirror, and is then reflected out an egress fiber. The LambdaRouter and other devices like it are now commercially deployed and offer speed, a relatively small footprint, bit rate and protocol transparency, nonblocking architecture, and highly developed database management. Fundamentally, these devices are very high-speed, high-capacity switches or cross-connect devices. They are not routers, because they do not perform layer-three functions. They will, however; all major manufacturers have announced plans to incorporate a layer-three routing function in their devices. Thus, optical networking is a major component of the modern transport network. Together with switching technologies like Frame Relay and ATM, and Physical-layer standards like SONET, SDH, and copperbased transport technologies, the current network can handle the transport requirements of any traffic type while overlaying QoS at the same time.

In a JFET, the current varies because of the effects of an electric field within the device. Charge carriers (electrons or holes) flow from the source (S) electrode to the drain (D) electrode. This results in a drain current, ID, that is normally the same as the source current, IS. The rate of flow of charge carriers that is, the current depends on the voltage at a control electrode called the gate (G). Fluctuations in gate voltage, EG, cause changes in the current through the channel, which is the path between the source and the drain. The current through the channel is normally equal to ID. Small fluctuations in EG can cause large variations in ID. This fluctuating drain current can produce significant fluctuations in the voltage across an output resistance.

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