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1. If your only concern is to improve performance, which RAID should you choose 2. When might you want to dedicate an entire drive set to tempdb

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This URL is provided only for human readability and should not be used by developers Developers should use the serialized element to retrieve the real folder location This value can be a regular file:// URL (as defined in RFC 1738 at http://wwwietforg/rfc/rfc1738txt) The serialized element contains a base64 encoded ShellLink that points to the location defined by the url element The Windows Shell automatically creates the ShellLink from the value of the url element If you take a closer look at one of the default libraries, such as Pictures, you ll notice that the Pictures library definition file is a bit more complex and contains a few more elements The iconReference element defines an icon resource using the standard Windows resource style for example, <iconReference> C:\Windows\system32\imageresdll,-65 </iconReference> This icon presents the library in Windows Explorer Some of you might wonder what does the 65 number represent.

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When you are designing your storage solution, consider that your choice of RAID for each volume affects the number of reads and writes that have to be processed. RAID 1 and RAID 10, for example, each generate one additional read operation for each write operation. RAID 5, however, generates four I/O operations (two reads and two writes) for each write. After I/Os are adjusted for these RAID types, you can determine the I/O load on each disk. Table 1-6 shows the calculation associated with each of these RAID types.

Table 1-6

RAID Type RAID 0 (stripe set without parity) RAID 1 (mirrored volume) RAID 5 (stripe set with parity) RAID 10 (stripe of mirrors)

I/Os per Disk Calculation (reads + writes) / number of disks [reads + (2 writes)] / 2 [reads + (4 writes)] / number of disks I/Os per disk = [reads + (2 writes)] / number of disks

Although all fault-tolerant RAID configurations increase the number of I/Os per formed by the system, it is important to remember that this increased number of I/Os is divided among more disks. As a result, if a RAID configuration is properly designed, it should have the net effect of lowering, not raising, the I/O load on each disk. In fact, a key concept in sizing the disk I/O subsystem is that the more physical disks you add to your RAID configuration, the fewer I/Os per disk. Because all disks have physical throughput limitations, such as 300 IOPS, it is often necessary to add disks to a configuration for the sole purpose of bringing the IOPS per disk down to a level that can be handled by each disk. (Note, however, that every system has a maximum I/O bus capacity beyond which I/O throughput cannot be increased merely by add ing disks.)

When deciding between SCSI and ATA disk types, understand that SCSI tends to be faster, smaller, more reliable and more expensive. Beyond SCSI, SATA and iSCSI offer even better performance at an even higher price.

Suppose that you want to design a RAID configuration for the logical volume stor ing your database. (For this example, assume that only one nonsystem database is being used on the system.) According to specifications given on the vendor Web site, the physical drives you will purchase for the database server have a through put capacity of 300 IOPS. Because I/O bottlenecks occur when throughput rates exceed 85 percent of capacity, you determine that the maximum acceptable throughput for any of these physical drives in a production environment is 255 IOPS (300 .85 = 255).

Well, this is the standard syntax for accessing resources in a compiled binary resource file A resource file can be a dll file or embedded in executable In both cases this index number points to the relevant resource elements in the list of resources Resources enumeration starts from the number zero and grows in a sequential way up to the total number of resource elements The minus sign represent the relevant offset of the resource file..

Exam Tip For the 70-443 exam, you need to have only a very general understanding of how to perform disk sizing. You will not need to perform any mathematical calculations such as those in this example.

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