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This assumption is justi ed by the large input resistance and large open-loop gain of the operational ampli er The model just introduced will be used to analyze three ampli er circuits in the next part of this section

ampli er of Figure 124 is a voltage ampli er; another type of operational ampli er, called a current or transconductance ampli er, is described in the homework problems

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+ AV(OL)vin _

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The GoTo statement allows you to repeat statements like a loop, or to skip over one or more statements and move to a later part of the program. While it was used extensively in the 1980s, it is now considered a poor choice for looping. The way this statement works it to jump from a GoTo statement with that label s name to the matching label in your program. The label can appear either before or after the GoTo statement. If it appears before, GoTo acts much like a loop. If it appears after, GoTo acts much like a call to a method. It is recommended that you use either a standard loop or a method instead of GoTo, but we are showing it here for completeness. VB .NET Dim numbers As Integer() = {5, 10, 15} ' Elements (0),(1), and (2) Dim i As Integer MyGotoLable1: 'Note that you need a colon here Console.WriteLine(numbers(i)) 'Shows 5 then 15 i = i + 1 If (i < 3) Then GoTo MyGotoLable1 End If C# int[] numbers = {5, 10, 15}; // Elements [0],[1], and [2] int i = 0; MyGotoLabel1: //Note that you need a colon here Console.WriteLine(numbers[i]); //Shows 5 then 10 then 15 i++; if (i < 3) { goto MyGotoLabel1; }

Integrated circuit operational amplifier (IC op-amp)

One of the more popular circuit con gurations of the op-amp, because of its simplicity, is the so-called inverting ampli er, shown in Figure 125 The input signal to be ampli ed is connected to the inverting terminal, while the noninverting terminal is grounded It will now be shown how it is possible to choose an (almost) arbitrary gain for this ampli er by selecting the ratio of two resistors The analysis is begun by noting that at the inverting input node, KCL requires that iS + iF = iin (1211)

+ _

The current iF , which ows back to the inverting terminal from the output, is appropriately termed feedback current, because it represents an input to the ampli er that is fed back from the output Applying Ohm s law, we may determine

9:

12

You can use this statement if you want to restart a loop without executing the remaining statements in that loop: VB .NET Dim numbers As Integer() = {5, 10, 15} Dim i As Integer = 0 While i < 3 If numbers(i) = 10 Then i = i + 1 Continue While 'Go back to the beginning of the while loop End If

each of the three currents shown in Figure 125: iS = vS v RS iF = vout v RF iin = 0 (1212)

(the last by assumption, as stated earlier) The voltage at the noninverting input, v + , is easily identi ed as zero, since it is directly connected to ground: v + = 0 Now, the open-loop model for the op-amp requires that vout = AV (OL) (v + v ) = AV (OL) v or v = vout AV (OL) (1214) (1213)

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