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A much better scheme for changing ac to dc is to use both halves of the ac cycle. Suppose you want to convert an ac wave to dc with positive polarity. Then you can allow the positive half of the ac cycle to pass unchanged, and flip the negative portion of the wave upside-down, making it positive instead. This is the principle behind full-wave rectification. One common full-wave circuit uses a transformer with a center-tapped secondary, as shown in Fig. 21-5A. The center tap, a wire coming out of the exact middle of the secondary winding, is connected to common ground. This produces out-of-phase waves at the ends of the winding. These two waves can be individually half-wave rectified, cutting off the negative half of the cycle. Because the waves are 180 degrees (half a cycle) out of phase, the output of the circuit has positive pulses for both halves of the cycle (Fig. 21-5B). In this rectifier circuit, the average dc output voltage is about 90 percent of the rms ac input voltage. The PIV across the diodes can be as much as 2.8 times the rms input voltage. Therefore, the diodes should have a PIV rating of at least 4.2 times the rms ac input. Compare Fig. 21-5B with Fig. 20-1B from the last chapter. Can you see that the waveform of the full-wave rectifier ought to be easier to smooth out In addition to this advantage, the full-wave, center-tap rectifier is kinder to the transformer and diodes than a half-wave circuit. Furthermore, if a load is applied to the output of the full-wave circuit, the voltage will drop much less than it would with a half-wave supply, because the output has more substance.

The principal form of optical switching is really nothing more than a sophisticated digital cross-connect system. In the early days of data networking, dedicated facilities were created by manually patching the end points of a circuit at a patch panel, thus creating a complete four-wire circuit. Beginning in the 1980s, digital cross-connect devices such as AT&T s Digital Access and Cross-Connect (DACS) became common, replacing the time-consuming, expensive, and error-prone manual process. The digital cross-connect is really a simple switch, designed to establish long-term temporary circuits quickly, accurately and inexpensively. Enter the world of optical networking. Traditional cross-connect systems worked fine in the optical domain, provided no problems were happening in the O-E-O conversion process. This, however, was one of the aspects of optical networking that network designers wanted to eradicate from their functional requirements. Thus was born the optical crossconnect switch. The first of these to arrive on the scene was Lucent Technologies LambdaRouter. Based on a switching technology called the MicroElectrical Mechanical System (MEMS), the LambdaRouter was the world s first all-optical cross-connect device. MEMS relies on micro-mirrors, an array of which is shown in Figure 6-23. The mirrors can be configured at various angles to ensure that

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Refer to the text in this chapter if necessary. A good score is at least 18 correct. Answers are in the back of the book. 1. In a PNP circuit, the collector (a) has an arrow pointing inward. (b) is positive with respect to the emitter. (c) is biased at a small fraction of the base bias. (d) is negative with respect to the emitter. 2. In many cases, a PNP transistor can be replaced with an NPN device and the circuit will do the same thing, provided that (a) the power supply or battery polarity is reversed. (b) the collector and emitter leads are interchanged. (c) the arrow is pointing inward. (d) Forget it! A PNP transistor can never be replaced with an NPN transistor. 3. A bipolar transistor has (a) three P-N junctions. (b) three semiconductor layers. (c) two N-type layers around a P-type layer. (d) a low avalanche voltage. 4. In the dual-diode model of an NPN transistor, the emitter corresponds to (a) the point where the cathodes are connected together. (b) the point where the cathode of one diode is connected to the anode of the other. (c) the point where the anodes are connected together. (d) either of the diode cathodes. 5. The current through a transistor depends on (a) EC. (b) EB relative to EC. (c) IB. (d) more than one of the above.

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