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FIGURE 7.1 Torque-angle curve for punching operation in Example 1. The dashed line indicates the average torque of 43 J/rad, and the shaded areas are each equal to the maximum energy variation of 247 J.

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

Find your MemoryBugsViewController class, and add a private member variable for the C++ class you just created in the header.

Since the torque-angle curve is steep at both ends, the area above the average torque line is the total area minus the small rectangle below the average. The energy variation is then U = 270 43.0 = 247 J 6 (7.3)

goto Listen Lock: low 4 low 6 T = INL & %00001111 high 6 C=C+1 if C>2000 then Begin lookup T,["0234567800019000"],J J=J-48 if J=0 then Off if C=1 and J=1 then Key if C=2 and J=2 then Key if C=3 and J=3 then Key if C=4 and J=4 then Key if C=5 and J=5 then Key if C=6 and J=6 then Key if C=7 and J=7 then Key if C=8 and J=8 then Key if C=9 and J=9 then Key goto Listen Key: G=G+1 if C=9 and J=9 and G=9 then Relay goto Listen Relay: pause 800 high 7 pause 200 goto Begin

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The relative speed between the cranking shaft and the flywheel is unimportant since the energy (torque times angle) is the same at either speed. Letting Cs = 0.10 for a moderate speed variation, Eq. (7.2) gives the necessary flywheel inertia: J= 247 0.51 = 5.67 N s2 m 202(0.10) (7.4)

For a steel-rim-type flywheel, assuming that 10 percent of the inertia is provided by the hub and spokes, the flywheel rim with a 0.5-m average rim diameter will weigh approximately W= Jg 0.9(5.67)(9.80) = = 0.800 kN r2 0.252(1000) a (7.5)

Using a density of 76.5 kN/m3, the necessary cross-sectional area is then given by A= 0.9(5.67)(9.80) Jg = = 0.006 66 m2 2 r 3 2 (76.5)(0.25)3(1000) a (7.6)

MemoryBugsViewController.h ... @interface MemoryTestViewController : UIViewController { struct TestCPPClass* mTestCpp; } ...

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Assuming that the speed is at its average during the peak torque of 774 J, the peak power required without any flywheel effect would be P = T = 774(20)(0.001) = 15.5 kW (7.7)

Without a flywheel, the design limitation on the speed fluctuation would have to be met using a nonuniform input torque. With the flywheel, the required power is determined from the average torque of 43.0 J: P = T = 43.0(20)(0.001) = 0.9 kW (7.8)

This shows that in addition to smoothing the machine operation, the flywheel actually reduces the size of the motor required.

7.2.2 Integration of the Torque-Angle Relation If the torque-angle curve for a machine cycle is available from experimental data or a dynamic analysis, U is determined from the areas between the curve and the average-torque line. If the external torque input or load is not constant, it can be combined with the torque-angle curve for the machine. If the loading torque and the driving torque are not synchronized or have an unknown phase difference, a worstcase combination should be used. The areas under the curve can be determined using a planimeter or by graphic or numerical integration. (See Example 4.) Unless Cs is accurately known and the curve is from a worst case or is highly repeatable, precision in integrating is not warranted.

listen again Tone detected, test code get DTMF data (low rs pin) activate chip-select pin remove upper bits using AND de-activate chip-select pin increment tone counter resets >2000 wrong entries convert tone to string convert string to value wrong digit "reset" IF all digits are in the correct order, AND after only one attempt, THEN increment the sequence counter variable : "G" ...

Note the use of the keyword struct. This is your C++ class. To use it within an Objective-C class, it needs to be declared with the struct keyword. If you leave the struct out of the declaration, the compiler will generate an error. At the top of your MemoryBugsViewController class implementation, include the following two classes.

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