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And the total energy dissipated in one actuation operation is E= T( P L)2 IP IL 2T(IP + IL) (ILTP + IPTL) (8.12)

The example code is clearly doing something stupid: it s trying to get the value of a property for an object that has already been released. If you build and run this code in the debugger, it should crash. In this case, the call stack should be inside viewDidLoad, and it s easy to see why it crashed. However, this kind of bug won t always crash at the

8.2.5 Energy Dissipation: Brakes Vehicle Brakes. When a vehicle of weight W is slowed from an initial velocity Vo to a final velocity Vf, the heat energy that the brakes must dissipate is equal to the change of kinetic energy E: E= W 2 (V o V 2 ) f 2g (8.13)

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In dealing with individual brakes, let W be that portion of the vehicle s weight for which the brake is responsible. Example 3. A sports car weighing 3185 lb [14.2 kilonewtons (kN)] has 62 percent of its weight on the front axle during an emergency stop. What energy must each of the front-wheel brakes dissipate in braking from 55 miles per hour (mph) [88 kilometers per hour (km/h)] to rest Local acceleration of gravity is 32.17 feet per second (ft/s) (9.81 m/s). Solution. Each front brake is responsible for a weight of W = 0.5(0.62)(3185) = 987 lb (4.39 kN) The initial velocity is Vo = 55 88 = 80.7 ft/s (24.6 m/s) 60

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

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Finally, the energy to be dissipated is E= W 987 2 (V o V f2) = [(80.7)2 02] 2g 2(32.17) = 99 900 lb ft (135.5 kN m) = 128.4 Btu [135.5 kilojoules (kJ)] Industrial Brakes. The approach is the same as for vehicular brakes. The heat energy the brake must dissipate equals the change in kinetic energy of the rotating machine: E= where, with n in rev/min, = 2 n 60 (8.15) I ( o2 f2) 2 (8.14)

point where the problem occurred. Sometimes it will crash later or in a different area of code. This can make tracking down the line that caused the problem quite difficult. However, NSZombieEnabled comes to the rescue! To enable this handy tool, in the project viewer find your MemoryBugs executable in the Groups & Files pane, and double-click it to open up the executable info window (see Figure 4-11).

In many industrial applications, the brakes are applied frequently. The average rate of heat dissipation is, for S stops per hour, Hav = ES 3600 (8.16)

Tensioning Applications. In tensioning applications, a continuous application of the brake is required, for example, in unwinding a roll of aluminum foil. The maximum torque occurs at the maximum roll diameter Dmax. It is Tmax = Dmax Ft 2 (8.17)

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The tension Ft is, for material width b and thickness t, Ft = wtb (8.18)

Typical values of tension per unit width and per unit thickness for a few materials are given in Table 8.6.

When the executable info window opens, click the Arguments tab at the top of the screen. The bottom pane of this window should be labeled Variables to be set in the environment. Click the + at the bottom to add a new variable. Name it NSZombieEnabled, and set its value to YES (see Figure 4-12).

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The rate at which heat is generated by the brake friction is Hav = FtVw (8.19)

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