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The app is telling you to set a breakpoint in malloc_error_debug, so do that now. To set a breakpoint on a symbol for which you don t have source code, you ll use the Breakpoints window. Open the Breakpoints window (Option-Command-B by default). Scroll to the bottom of the window, and you should see a blue box with the text Double-Click for Symbol next to it, as shown in Figure 4-9.

TABLE 13-1

where FS, FD, and FL are the starting, prime-mover, and load factors, respectively. Recommended values for these factors are given in Tables 8.3 to 8.5. Note that if each factor is unity, the service factor is unity also. But the service factor KS will usually be greater than unity. Indeed, an old rule of thumb was that the clutch should be designed for a torque capacity at least twice the nominal torque. Example 1. A multicylinder diesel engine is used to drive an electric generator in a hospital s emergency-power facility. What service factor should be used Solution. From Table 8.3, a reasonable selection of values for the torque factors is FS = 2, FD = 1.5, and FL = 1.0. The corresponding service factor is KS = [22 + (1.5)2 + (1.0)2 2]1/2 = 2.29

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Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

8.15 Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

8.2.2 Equivalent Inertias Two shafts geared together and rotating at different speeds are shown in Fig. 8.11a. The inertias I1 and I2 are each assumed to include the corresponding shaft and gear. For design calculations, it is necessary to have an equivalent inertia for the whole system referred to a single shaft. Figure 8.11b and c shows this. In each case an equivalent inertia has been added to the shaft. So I2 is the equivalent inertia on shaft 1 of shaft 2 and its hardware. Similarly, I1 is the equivalent inertia on shaft 2 of shaft 1 and its hardware. A simple way to find the equivalent inertia is to equate the kinetic energies of the actual and equivalent inertias. Thus, to find the equivalent inertia I2 referred to shaft 1 (Fig. 8.11b), we write 1 1 I 2 2 = I2 2 1 2 2 2 Thus I2 = 2 1

Double-click in that box, and you ll be prompted to enter a symbol name. Enter malloc_error_break, and press Enter. The Breakpoints window should now show a new breakpoint set on that function. Run the app again (via Run Debug), and this time, you should hit the breakpoint. If you look at the call stack in the debugger, you should see something like Figure 4-10.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

(8.3)

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

FIGURE 8.11 Equivalent inertia. I1, I2 = inertia of input and output shafts, respectively; I = equivalent inertia. (a) Original configuration; (b) equivalent system referred to input shaft; (c) equivalent system referred to output shaft. For a more extensive treatment of equivalent inertias, see Suggested Reading list, Mischke.

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If you click the call stack at [MemoryBugsViewController viewDidLoad], you ll see that the breakpoint was hit on the second release of the date object. This tells you exactly where the problem occurred. Now you can figure out why it was released twice and fix your bug!

1 2

(8.4)

(8.5)

where the equivalent inertia of the ith shaft is referred to the jth shaft. Equation (8.5) can be used to reduce a machine with several shafts connected by gears or flexible connectors to a single equivalent shaft. Example 2. For the two-shaft machine in Fig. 8.11a, the inertias are I1 = 2.88 pound-inch-square seconds (lb in s2) [0.3254 kilogram-square meters (kg m2)] and I2 = 0.884 lb in s2 (0.09988 kg m2). The pitch diameters of the gears are D1 = 4 in [0.102 meter (m)] and D2 = 7 in (0.178 m). What is the equivalent inertia of shaft 2 referred to shaft 1

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