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Another alternative for the breakdown of macro-activities into operational tasks is to use software life-cycle macro-phases2 and to map these with the process model adopted in your own quality management system, or to use an external standard process model such as CMMI-DEV, SPICE (ISO/IEC 15504-5), or ISO/IEC 12207 Use of one of these will provide a framework to ensure that all standard and repeated activities are included As your projects will then share the same definitions, ambiguities will be minimized, and this will also allow the comparison of projects The result will be a three-tier WBS: Macro-Software Life-Cycle Phase (for example, Design ) Process (according to the chosen process model, for example, Architectural Design ) Task (according to the chosen process model, for example, Review Architectural Design Specification ) Depending upon the process model chosen, it is possible to have a different number of process groups (or categories, depending upon the terminology used) For instance: CMMI-DEV has distributed its 22 process areas into four process categories (Project Management, Process Management, Support, and Engineering) ISO/IEC 15504-5 distributed its 48 processes into three main blocks of processes (Primary, Organizational, Support) for a total of nine process groups (Primary: Acquisition, Supply, Engineering, Operation; Organizational: Management, Process Improvement, Resource and Infrastructure, Reuse; Support: Support) Figure 10-1 compares the two models contents against those categories Two main questions arise from such classification into process categories: What is the impact of the number of process categories on the WBS From a practical viewpoint, some useful information can be gained from a Gantt chart structured using these classifications For instance, it would allow the following: Easier matching of activity types to the related personnel skills required This would provide a more granular classification of a generic analysis process, which would lead to different allocations (and related costs) for functional/business analysts and for technical analysts.

8 6 4 2 0 10 1 100 101 102 103 104 Radian frequency (logarithmic scale) 105

0 10 20 10 1 100 102 103 104 101 Radian frequency (logarithmic scale) 105

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are investigated in the homework problems One remark that should be made in passing, though, pertains to the exclusive use of capacitors in the circuits analyzed thus far One of the advantages of op-amp lters is that it is not necessary to use both capacitors and inductors to obtain a band-pass response Suitable connections of capacitors can accomplish that task in an op-amp This seemingly minor fact is of great importance in practice, because inductors are expensive to mass-produce to close tolerances and exact speci cations and are often bulkier than capacitors with equivalent energy-storage capabilities On the other hand, capacitors are easy to manufacture in a wide variety of tolerances and values, and in relatively compact packages, including in integrated circuit form Example 125 illustrates how it is possible to construct active lters with greater frequency selectivity by adding energy-storage elements to the design

Determine the closed-loop voltage gain as a function of frequency for the op-amp circuit of Figure 1228

comparison operators, but are specifically made for the Boolean values of True and False. Their purpose is to allow you to compare two operands and come to a conclusion about the overall expression based on the following True tables (see Tables B-7 through B-10).

Known Quantities: Feedback and source impedances Find:

A(j ) =

CMMI Project Management Process Management Support Engineering ISO 15504 Acquisition (ACQ) Supply (SUP) Engineering (ENG) Operation (OPE) Support (SUP) Management (MAN) Process Improvement (PIM) Resource & Infrastructure (RIN) Reuse (REU)

Vout (j ) VS (j )

Schematics, Diagrams, Circuits, and Given Data: R2 C = L/R1 = 0 Assumptions: Assume ideal op-amp Analysis: The expression for the gain of the lter of Figure 1228 can be determined by using equation 1245:

A(j ) =

VB .NET Dim a As Boolean = True Dim b As Boolean = False If a And b Then Console.WriteLine("True") Else Console.WriteLine("False") 'Show False End If C# bool a = true; bool b = false ; if (a & b) { Console.WriteLine("True");} else { Console.WriteLine("False");} //Shows False Notice that with the And operator, only one operand has to evaluate to False before the conclusion is False. Both VB .NET and C# have a short-circuit version of the And/& logical operator. This short-circuit version will not compare the second operand if the computer already knows that the first operand is False. This saves the computer time and can make your program run a bit faster.

ZF (j ) Vout (j ) = VS (j ) ZS (j )

12

Figure 10-1

where ZF (j ) = R2 || 1 R2 R2 = = j C 1 + j CR2 1 + j / 0 L R1 = R1 (1 + j / 0 )

= R1 + j L = R1 1 + j Thus, the gain of the lter is: A(j ) =

R2 1+j / 0

VB .NET Dim a As Boolean = True Dim b As Boolean = False If a AndAlso b Then Console.WriteLine("True") Else Console.WriteLine("False") 'Show False faster End If C# bool a = true; bool b = false ; if (a && b) { Console.WriteLine("True");} else { Console.WriteLine("False");} //Shows False faster The inclusive Or operator evaluates to true as long as one of the operands it true.

R1 (1 + j / 0 )

R2 /R1 (1 + j / 0 )2

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